Answer:
right
Step-by-step explanation:
s
a
k
+
1
=
a
k
+
2
and
a
1
=
6
a
2
=
a
1
+
2
=
6
+
2
=
8
a
3
=
a
2
+
2
=
8
+
2
=
10
a
4
=
a
3
+
2
=
10
+
2
=
12
and
a
5
=
a
4
+
2
=
12
+
2
=
14
and hence first five terms are
{
6
,
8
,
10
,
12
,
14
}
As
a
k
+
1
=
a
k
+
2
, each term is
2
more than previous term
it is an arithmetic sequence with first term as
a
1
and common difference
d
and hence
n
t
h
term is
a
n
=
a
1
+
(
n
−
1
)
d
and hence
n
t
h
term of the sequence is
a
n
=
6
+
(
n
−
1
)
×
2
=
6
+
2
n
−
2
=
2
n
+
4
