Step-by-step explanation:
The given quadratic equation is :
[tex]13x^2 +1 = -10x\\\\or\\\\13x^2+10x+1=0[/tex]
The formula to solve a quadratic equation is :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
Put a = 13, b = 10 and c = 1
So,
[tex]x=\dfrac{-10\pm \sqrt{10^2-4(13)(1)} }{2(13)}\\\\x=-0.118, -0.651[/tex]
Hence, this is the required solution.
