Answer:
V = 11.2 L
Explanation:
Hello there!
In this case, according to the ideal gas equation:
[tex]PV=nRT[/tex]
It is possible to compute the volume as shown below:
[tex]V=\frac{nRT}{P}[/tex]
Whereas the moles are computed are computed given the mass and molar mass of oxygen:
[tex]n=16g*\frac{1mol}{32g} =0.5mol[/tex]
Now, since the STP stands for a temperature of 273.15 K and a pressure of 1 atm, the resulting volume is:
[tex]V=\frac{0.5mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=11.2L[/tex]
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