Answer:
[tex]v=11.135m/s[/tex]
Explanation:
From the question we are told that
Mass [tex]m=0.40kg[/tex]
Frictional friction [tex]f=1.2[/tex]
Spring constant [tex]k=800N/m[/tex]
Compressed [tex]x=0.50[/tex]
Generally the energy balance equation is mathematically given as
[tex]1/2kx^2=f*30+m*g*sin \theta*30+1/2m*v^2[/tex]
if [tex](sin=10/30-1/3)[/tex]
[tex]1/2(800)(0.5)^2=(1.2)*30+(0.4)*9.8*1/3*30+1/2(0.4)*v^2[/tex]
[tex]100=36+39.2+0.20v^2[/tex]
[tex]v^2=\frac{24.8}{0.20}[/tex]
[tex]v=\sqrt{124}[/tex]
[tex]v=11.135m/s[/tex]
