Answer:
d = 225 m
Step-by-step explanation:
Initial speed, u = 5 m/s
Final speed, v = 40 m/s
Time, t = 10 s
Acceleration,
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{40-5}{10}\\\\a=3.5\ m/s^2[/tex]
Let d is the distance covered. Using second equation of motion to find it i.e.
[tex]d=ut+\dfrac{1}{2}at^2\\\\d=5\times 10+\dfrac{1}{2}\times 3.5\times 10^2\\\\d=225\ m[/tex]
So, it will cover 225 m.
