Wedmbiluli4nura Wedmbiluli4nura
  • 19-11-2016
  • Mathematics
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Integral of (3x-2)/(x-1)^2

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syed514
syed514 syed514
  • 20-11-2016
(3x−2)/(x−1)^2=A/(x−1) + B/x(x−1)^2
                       =[A(x−1)+Bx(x−1)] / 2
3x-2=A(x-1)+Bx
3x-2=x(A+B)-A
A+B=3
-A=-2=>A=2
A+B=3=>2+B=3=>B=1

lets check our partial fraction we have 2/(x−1) + x/(x−1)^2 = [2(x−1)+x] / (x−1)^2
                               =(3x−2) / (x−1)^2
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