AliceinWonderLand77 AliceinWonderLand77
  • 17-11-2016
  • Mathematics
contestada

What equation is graphed in this figure?

y−3=13(x+1)y−3=13(x+1)

y−5=3(x−1)y−5=3(x−1)

y−4=−13(x+2)y−4=−13(x+2)

y+2=−3(x−1)

Respuesta :

merissahahn1027
merissahahn1027 merissahahn1027
  • 17-11-2016
x^2+y^2=9 (an equation of a circle with a radius of 3)sin(x)+cos(y)=0.52x-3y=1cos(x^2)=y(x-3)(x+3)=y^2y=x^2
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Creatorjojo
Creatorjojo Creatorjojo
  • 05-11-2018

The Answer would be B. y−5=3(x−1)y−5=3(x−1)

Good Luck =D

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