21-03-2021
Mathematics

contestada

Tentukan nilai limit x->3 x2-9/x-3

Respuesta :

jimrgrant1 jimrgrant1

21-03-2021

Answer:

6

Step-by-step explanation:

Factor the numerator, difference of squares

[tex]\frac{(x-3)(x+3)}{x-3}[/tex] ( cancel x- 3 on numerator/ denominator )

= x + 3

limit as x → 3 = 3 + 3 = 6

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