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Consider the following balanced chemical reaction:

N2 + 3 H2 → 2 NH3

If you needed to produce 41.0 g of NH3, how many grams of H2 would you need?

Respuesta :

Answer:

7.27 grams

Explanation:

Format= starting amount (g)·(1 mol/molar mass)·(amount of wanted/amount of starting)·(molar mass of wanted/1 mol)

[tex]41.0 x \frac{1 mol}{17.031}x\frac{3 H2}{2NH3} x\frac{2.016}{1 mol} =7.27[/tex]

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