i need help can you explain how to do it
Answer:
-7.
Step-by-step explanation:
(x²+t²x+t³+8)`=(x²)`+(t²x)`+(t³)`+(8)`=2x*x'+2t*x+t²*x'+3t²;
[tex]x'=\frac{2tx+3t^2}{t^2+2x};[/tex]
[tex]x'(-2;-4)=\frac{2*2*4+3*4}{4-8}=-7.[/tex]