Answer:
Option A
Step-by-step explanation:
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
AC² = 6² + 5²
AC = [tex]\sqrt{61}[/tex]
Similarly, by applying Pythagoras theorem in ΔACD,
AD² = AC² + CD²
(10)² = [tex](\sqrt{61})^2[/tex] + x²
x² = 100- 61
x² = 39
x = √(39)
Option A will be the answer.
