Answer:
DF = 28 units
AC = 64 units
CF = 32 units
Step-by-step explanation:
In the given triangle ABC points D, E and F are the midpoints of the sides AB, BC and AC.
By midsegment theorem,
"Segment joining the midpoints of each side is parallel and measure the half of the opposite side"
DF = [tex]\frac{1}{2}(BC)[/tex]
= [tex]\frac{56}{2}[/tex]
= 28 units
AC = 2(DE)
= 2 × 32
= 64 units
CF = [tex]\frac{1}{2}(AC)[/tex]
= [tex]\frac{64}{2}[/tex]
= 32 units
