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19-02-2021
Mathematics

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In ΔIJK, i = 74 inches, j = 23 inches and ∠K=20°. Find the area of ΔIJK, to the nearest square inch.

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abidemiokin abidemiokin

20-02-2021

Answer:

291in^2

Step-by-step explanation:

Using the formula

Area of the triangle = 1/2absin theta

A = 1/2ijsin<K

Given

i = 74in

j = 23in

<K = 20 degrees

Area = 1/2 * 74*23sin20

Area = 37*23sin20

Area = 852sin20

Area = 291.059in^2

Hence the area of the triangle to nearest square inch is 291in^2

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