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  • 18-02-2021
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if sin a=-4/5 find cos a​

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Аноним Аноним
  • 18-02-2021

Answer:

sin a=-4/5

we have sina=perpendicularp/hypotenuseh=-4/5

let p=-4k

h=5k

by Pythagoras theorem

h²=p²+b²

(5k)²=(-4k)²+b²

25k²-16k²=b²

(3k)²=b²

b=√(3k)²=3k

now

cos a =b/h=3k/5k=3/5

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