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A line passes through the point (-4,7) and has a slope of 3/2
Write an equation in slope-intercept form for this line.

A line passes through the point 47 and has a slope of 32 Write an equation in slopeintercept form for this line class=

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Answer:

[tex]y=\frac{3}{2}x + 13[/tex]

Step-by-step explanation:

Given that [tex]x_{1}[/tex] = -4 and [tex]y_{1}[/tex] = 7 (from the point given) and m = [tex]\frac{3}{2}[/tex], we will use the equation [tex]y - y_{1} =m(x-x_{1})[/tex]. Therefore, when we substitute the given values to the equation:

y - y1 = m(x - x1)

y - 7 = 3/2(x - (-4))

y - 7 = 3/2(x + 4)

y - 7 = 3/2x + 6

y = 3/2x + 6 + 7

y = 3/2x + 13

Answer:

y = [tex]\frac{3}{2}[/tex] x + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = [tex]\frac{3}{2}[/tex] , then

y = [tex]\frac{3}{2}[/tex] x + c ← is the partial equation

To find c substitute (- 4, 7) into the partial equation

7 = - 6 + c ⇒ c = 7 + 6 = 13

y = [tex]\frac{3}{2}[/tex] x + 13 ← equation of line

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