Answer:
103.65 mph
Step-by-step explanation:
A bearing of 250 deg is 200 deg on the coordinate plane.
Find the x- and y-components of the speed vectors. Add them. Then find the magnitude of the resultant.
Hx = 110 cos 200° = -103.366
Hy = 110 sin 200° = -37.622
Ax = 0
Ay = 30
Hx + Ax = -103.366
Hy + Ay = -37.622 + 30 = -7.622
sqrt(-103.366^2 + -7.622^2) = 103.65
Answer: 103.65 mph
