Answer:
v = 108 m/s.
Explanation:
Given that,
The position of a particle moving on a straight line is given by :
[tex]X =12 + 18t + 9t^2[/tex]
We need to find the instantaneous velocity at t=5s.
Velocity, [tex]v=\dfrac{dX}{dt}[/tex]
So,
[tex]v=\dfrac{d(12 + 18t + 9t^2)}{dt}\\\\=18+18t[/tex]
Instantaneous velocity at t = 5 s will be :
v = 18+18t
v = 18+18(5)
= 18 + 90
= 108 m/s
So, the instantaneous veloctiy at t=5s is 108 m/s.
