kiluvaevans kiluvaevans
  • 17-01-2021
  • Mathematics
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Using first principal find the gradient of the curve whose equation is y=x^5. show working pleas​

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xero099
xero099 xero099
  • 22-01-2021

Answer:

The gradient of [tex]y = x^{5}[/tex] is [tex]\frac{dy}{dx} = 5\cdot x^{4}[/tex].

Step-by-step explanation:

Geometrically speaking, the gradient of a curve is the slope of the tangent line at a given point of the curve. From perspective of Differential Calculus, the gradient is the first derivative of the curve. Let [tex]y = x^{5}[/tex], then the gradient of the curve is:

[tex]\frac{dy}{dx} = 5\cdot x^{4}[/tex] (1)

The gradient of [tex]y = x^{5}[/tex] is [tex]\frac{dy}{dx} = 5\cdot x^{4}[/tex].

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