Answer:
Option B
Step-by-step explanation:
Given fraction is,
[tex]\frac{6}{6+\sqrt{12x}}[/tex]
We will solve his fraction by rationalizing the denominator of this fraction.
[tex]\frac{6}{6+\sqrt{12x}}=\frac{6}{6+\sqrt{12x}}\times \frac{6-\sqrt{12x}}{6-\sqrt{12x}}[/tex]
[tex]=\frac{6(6-\sqrt{12x})}{6^{2}-(\sqrt{12x})^2}[/tex]
[tex]=\frac{6(6-\sqrt{12x})}{36-12x}[/tex]
[tex]=\frac{6(6-\sqrt{12x})}{6(6-2x)}[/tex]
[tex]=\frac{6-\sqrt{12x}}{6-2x}[/tex]
Therefore, Option B will be the correct option.
