ipfrm8vx2b ipfrm8vx2b
  • 20-11-2020
  • Physics
contestada

If you drop a rock off a cliff and it hits the ground 3 seconds later how tall is that cliff

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katelynnewberry011
katelynnewberry011 katelynnewberry011
  • 20-11-2020

Answer:

Basic kinematics, negating drag and assuming ideal conditions, we use the equation:

d=vi*t+1/2*a*t^2

Since vi is 0 (we know this because you’re dropping it, not throwing it)…

…and the only acceleration acting on it is gravity, a=9.8 m/s^2…

…we get

d=1/2(9.8)(5)^2

Explanation:

Some quick mental math tells us that this is about 125 m.

Plugging it in, we find it to be 122.5 m.

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