Answer:
Explanation:
in all the question we have to use same technique
in 1 question
weight/force exerted by dorje(F)=1500N
total surface area of sole(A)=0.5m²
we know that,
P=[tex]\frac{F}{A}[/tex]
or, p=[tex]\frac{1500}{0.5}[/tex]
∴ P=3000pa
in question 2nd
pressure(P)=40 pa
force exerted by block(F)=80N
we know,
pressure(P)=[tex]\frac{Force(F)}{Area(a)}[/tex]
area=[tex]\frac{80}{40}[/tex]
∴area =2m
ow you can do other by yourself
