Answer:
A) 1 : 4
B) 1 : 2
C) Base of M = 10 units
Step-by-step explanation:
A)
The ratio of the area of triangle M to triangle N
[tex] \frac {40}{160}= \frac{1}{4} = 1 : 4[/tex]
B)
The ratio of the side lengths of triangle M to triangle N
[tex]\sqrt{ \frac {40}{160}} = \sqrt{\frac{1}{4}} \\\\={\frac{1}{2}} \\\\
=1 : 2[/tex]
C) Let the base of triangle M be b units.
[tex] \sqrt{ \frac {40}{160}} = \frac{b}{20}\\\\
\frac{1}{2}= \frac{b}{20}\\\\
2b = 20\\\\
b = \frac{20}{2} \\\\
b = 10[/tex]
