Answer:
v = 1 or -3
Step-by-step explanation:
2v^2 + 4v = 6
take 2 as common
2(v^2 + 2v = 3)
v^2 + 2v = 3
Now,
v^2 + 2v - 3 = 0
v^2 - v + 3v - 3 = 0
v(v - 1) + 3(v - 1) = 0
(v - 1) (v + 3) = 0
<=>v²+2v-3=0
<=>v²-v+3v-3=0
<=>v(v-1)+3(v-1)=0
<=>(v-1)(v+3)=0
<=>*v-1=0
v=1
*v+3=0
v=-3
