Respuesta :

konrad509
[tex]x^2-8x+12=\\ x^2-6x-2x+12=\\ x(x-6)-2(x-6)=\\ (x-2)(x-6)[/tex]
luana
[tex]x^2-8x+12=0\ \ \ | write\ -8x\ as\ -6x-2x\\\\ x^2-6x-2x+12=0\\\\x(x-2)-6(x-2)=0\\\\(x-6)(x-2)=0\\\\ Factor\ form\ is\ (x-6)(x-2)=0.[/tex]