zayrobciel zayrobciel
  • 19-10-2020
  • Mathematics
contestada

(3+sqrt-16)(6-sqrt-64)

Respuesta :

Spire Spire
  • 19-10-2020

Answer:

12i + 9

Step-by-step explanation:

Since sqrt of negative numbers cannot exist, they are numbers followed by the letter I.

sqrt -16=4i

sqrt -64=8i

3 and 6 cannot be grouped with them, so you would add these two

3+6=9

8i+4i=12

I believe this would be the answer:

12i + 9.

Answer Link
meso18 meso18
  • 19-10-2020

Answer:

18-32i

Step-by-step explanation:

(3+sqrt(16i)(6-sqrt(64i)

= 18-32i

Answer Link

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