Answer:
B. [tex]\frac{-3}{4}[/tex]±[tex]\frac{\sqrt{41} }{4}[/tex]
Step-by-step explanation:
First, substitute the equation into the quadratic formula.
[tex]x=\frac{b+-\sqrt{(b^{2} )-4(a)(c)} }{2a}[/tex]
x=[tex]\frac{-3+-\sqrt{(3)^2-4(-2)(4)} }{4}[/tex]
Solve for x.
x= [tex]\frac{-3+-\sqrt{9+32} }{4}[/tex]
x=[tex]\frac{-3+-\sqrt{41} }{4}[/tex]
The answer is x= [tex]-\frac{3}{4}[/tex]±[tex]\frac{\sqrt{41} }{4}[/tex]
