Answer:
Mass of MgSO₄ = 37.61 g
Explanation:
Given data:
Mass of MgSO₄ needed = ?
Volume of solution = 0.250 L
Molarity of solution = 1.25 M
Solution:
Formula;
Molarity = number of moles of solute / L of solution
Now we will put the values in formula:
1.25 M = number of moles of solute / 0.250 L
Number of moles of solute = 1.25 M ×0.250 L
(M = mol/L)
Number of moles of solute = 0.3125 mol
Mass = number of moles × molar mass
Mass = 0.3125 mol × 120.366 g/mol
Mass = 37.61 g
