Answer:
Step-by-step explanation:
12x²-3x=2
[tex]x^2-\frac{1}{4}x=\frac{1}{6}\\x^2-\frac{1}{4}x+\frac{1}{64}=\frac{1}{6}+\frac{1}{64}\\(x-\frac{1}{8})^2=\frac{ 32+3 }{192}=\frac{35}{192}\\\\(x-\frac{1}{8} )^2-(\sqrt{\frac{35}{192} } )^2=0\\(x-\frac{1}{8} +\sqrt{\frac{35}{192} } )(x-\frac{1}{8} -\sqrt{\frac{35}{192} } )=0[/tex]
