Step-by-step explanation:
[tex]y = 16 {x}^{2} + 1 \\ \\ y - 1 = 16 {x}^{2} \\ \\ \frac{y - 1}{16} = {x}^{2} \\ \\ \pm \sqrt{ \frac{y - 1}{16} } = x \\ \\ x = \pm \frac{ \sqrt{y - 1} }{4} \\ \: this \: is \: the \: required \: inverse \: \\ equation \: of \: y = 16 {x}^{2} + 1[/tex]
