cisabelr
cisabelr
18-09-2016
Mathematics
contestada
How to graph the following: y=-3(x-2)^2+4
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apologiabiology
apologiabiology
18-09-2016
ok sowe have
y=a(x-h)^2+k
h,k is vertex
y=-3(x-2)^2+4
vertex is (2,4)
since a is negative, graph opens down
so at point (2,4)< draw a parabola opening down, going through point (0,4)
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