26y⁴+39y³-13y² ÷(-13y²)
26y⁴+39y³ + 1 ( any expression divided by itself equals )
Answer:
- 2y² - 3y + 1
Step-by-step explanation:
Given
[tex]\frac{26y^4+39y^3-13y^2}{-13y^2}[/tex]
= [tex]\frac{26y^4}{-13y^2}[/tex] + [tex]\frac{39y^3}{-13y^2}[/tex] - [tex]\frac{13y^2}{-13y^2}[/tex]
= - 2y² - 2y + 1
