evelynd06 evelynd06
  • 20-09-2020
  • Mathematics
contestada

B is between line AC. If AB = x^2– 3x, BC = 9x, and AC = 16. Solve for x.

Respuesta :

Hrishii
Hrishii Hrishii
  • 20-09-2020

Answer:

x = {- 8, 2}

Step-by-step explanation:

Since, B is between line AC.

[tex]\therefore AB + BC = AC\\

\therefore x^2 - 3x + 9x = 16\\

\therefore x^2 - 3x + 9x - 16=0\\

\therefore x^2 + 6x - 16=0\\

\therefore x^2 + 8x - 2x- 16=0\\

\therefore x(x +8) - 2(x + 8)=0\\

\therefore (x+8)(x-2)=0\\

\therefore x + 8 = 0\: or \: x-2=0\\

\therefore x = - 8 \:or\: x = 2\\

\huge \orange {\boxed {\therefore x = \{-8,\: 2\}}} [/tex]

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