justintobias566 justintobias566

20-09-2020
Mathematics

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Please help with number 6 ASAP I will mark branlist

Please help with number 6 ASAP I will mark branlist class=

Respuesta :

ZJSG09112007 ZJSG09112007

20-09-2020

Answer:

12

Step-by-step explanation:

[tex]4\sqrt{9}\\\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=4\sqrt{3^2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{a^2}=a,\:\quad \:a\ge 0\\\sqrt{3^2}=3\\\\=4\times\:3\\\\=12[/tex]

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