Answer:
[tex]\frac{13}{20}[/tex]
Step-by-step explanation:
The absolute value function always gives a positive value, that is
| - a | = | a | = a
Given
[tex]\frac{|2y^3+3|}{4x}[/tex] substitute x = 5 and y = - 2 into the expression
= [tex]\frac{|2(-2)^3+3|}{4(5)}[/tex]
= [tex]\frac{|2(-8)+3|}{20}[/tex]
= [tex]\frac{|-16+3|}{20}[/tex]
= [tex]\frac{|-13|}{20}[/tex]
= [tex]\frac{13}{20}[/tex]
