Answer:
[tex]d=0.697\ lb/in^3[/tex]
Explanation:
Given that,
The density of gold is 19.3 g/cm³.
We need to find the density in units of lbs/in³. We know that,
1 in = 2.54 cm and 1 lb = 453.6 g
So,
[tex]d=19.3\ \dfrac{g}{cm^3}\\\\=19.3\times \dfrac{\dfrac{1}{453.6 }\ g}{\dfrac{1}{(2.54\ cm)^3}}\\\\d=0.697\ lb/in^3[/tex]
Hence, the correct option is (c).
