christopherbaut527
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A 1200 kg car is put into neutral and pushed by 2 students. The first student pushed the car forward with 200 N of force. The second student pushed with 250 N of force in the same direction. What is the acceleration the car experienced.

Respuesta :

MathPhys

Explanation:

∑F = ma

200 N + 250 N = (1200 kg) a

a = 0.375 m/s²

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In first case

[tex]\green\star[/tex]m = 1200 kg

[tex]\blue\star[/tex]force exerted by first student and second student = 200N+250N

[tex]\green\star[/tex]a = ?

[tex]\blue\star[/tex]F = m×a

[tex]\green\star[/tex]200N + 250 = 1200kg × a

[tex]\blue\star[/tex]a = [tex]\dfrac{450}{1200}[/tex]

[tex]\green\star[/tex]a = 0.375 m\s

Hope it helps.

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