srodriguez3943 srodriguez3943
  • 18-08-2020
  • Mathematics
contestada

factorise : 64a cube minus 27b cube minus 144a square b plus 108ab square ​ .


Plz Answer this question

Respuesta :

samuelonum1
samuelonum1 samuelonum1
  • 20-08-2020

Answer:

The answer is [tex]4a(16a^2+27b^2)-3b(9b^2+48b)[/tex]

Step-by-step explanation:

step one:

let us re-write the expression in mathematical terms for clarity

we have the expression stated  below

[tex]64a^3-27b^3-144b^2+108ab^2[/tex]    

step two:

We are going to collect like terms before factorization we have

    [tex]64a^3+108ab^2-27b^3-144b^2[/tex]

We can now factorize the expression we have  

[tex]4a(16a^2+27b^2)-3b(9b^2+48b)[/tex]

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