Answer:
we will take a 100g sample of this solution for our convenience
so , there is 15 g kBr in this 100g solution
we know that molality is the number if moles of solute / mass of solvent in kg
we need to find the number of moles in 15g kBr
no of moles = 15/119 s
moles = 0.126 moles/ 100g
multiplying both the numerator and the denominator by 10 to get 1 kg in denominator
= 1.26 moles / 1 kg
Hence, the molality is 1.26
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