Answer:
Explanation:
object distance u = -58.2 cm .
Focal length f = -18.1 cm .
from lens formula
[tex]\frac{1}{v} - \frac{1}{u} =\frac{1}{f}[/tex]
Putting the values in the formula
[tex]\frac{1}{v} + \frac{1}{58.2} =- \frac{1}{18.1}[/tex]
[tex]\frac{1}{v} + .017=-.055[/tex]
[tex]\frac{1}{v}[/tex] = - .072
v = -13.80 cm
magnification
[tex]\frac{v}{u}[/tex]
= [tex]\frac{13.80}{58.2}[/tex]
= .237 .
