Answer:
Option B is the correct answer
Step-by-step explanation:
Center of the circle lie on point (-1, - 3) = (h, k)
[tex] \implies \: h = - 1 \: \: k = - 3 \\radius \: r \: = 2 \\ equation \: of \: circle \: in \: standard \: form \: \\ is \: given \: as : \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ {(x + 1)}^{2} + {(y + 3)}^{2} = {2}^{2} \\ \purple{ \boxed{ \bold{ {(x + 1)}^{2} + {(y + 3)}^{2} = 4}}}[/tex]
