s15159851
s15159851 s15159851
  • 18-06-2020
  • Mathematics
contestada

Please help……………………………………!!!!!!!!!

Please help class=

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 18-06-2020

Answer:

4 k^4

Step-by-step explanation:

(64 k^12) ^ 1/3

We know (ab)^c = a^c * b^c

64 ^ 1/3   k^12^1/3

4 * k^12^1/3

We know a^b^c = a^(b*c)

4 k^(12*1/3)

4 k^4

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