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20-05-2020
Chemistry

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How many moles of NaCl are present in 530 ml of a 1.52m NaCl solution

Respuesta :

aabdulsamir aabdulsamir

25-05-2020

Answer:

805.6 moles

Explanation:

Molarity = 1.52mL

Volume = 530mL

1.52 moles is present in 1mL,

1mL = 0.001L

1.52 moles = 0.001L

X moles = 0.53L

X = (1.52 × 0.53) / 0.001

X = 805.6moles

805.6moles is present in 530mL or 0.52L

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