Answer:
As shown in picture, we have
[tex]v = \frac{8\sqrt{3}}{cos 30} = \frac{8\sqrt{3}}{\frac{\sqrt{3}}{2} } = 16[/tex]
Hope this helps!
:)
Explanation:
Let say right triangle ABC has A = 90 deg.
=> BC is hypotenuse.
=> BC = AC x BC/AC = AC/(AC/BC) =AC/cosC.
That's the way we've done!
