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  • 17-05-2020
  • Mathematics
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[tex](3 {x}^{3} ) + \sqrt{16 {x}^{12} } - 8 {x}^{4} [/tex]
solve​

Respuesta :

PollyP52 PollyP52
  • 17-05-2020

Answer:

3x^3 + 4x^6 - 8x^4  or

x^3( 4x^3 - 8x + 3).

Step-by-step explanation:

 3x^3 + √(16x^12) - 8x^4

= 3x^3 + 4x^6 - 8x^4

We can factor this;  to give

x^3( 4x^3 - 8x + 3)

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