Answer: (2y+3)(3x+y-1)
Step-by-step explanation:
First regroup the terms.
6xy+9x+2y^2+y-3
Second factor 3x out of 6xy+9x
3x(2y)+9x+2y^2+y-3
3x(2y)+3x(3)+2y^2+y-3
And you get
3x(2y+3)+2y^2+y-3
Third factor by grouping
