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A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular circuit?
A. 4.8 V
B. 387 A
C. 387 V
D. 4.8 A

Respuesta :

skyp
voltage = current × resistance

plug in all the numbers

voltage = 9 × 43

now simplify

voltage = 387 V = C.

Answer : The correct option is, (C) 387 V

Solution : Given,

Electric current = 9 A

Resistance = 43 ohms

Using ohm's law,

[tex]V=I\times R[/tex]

V = applied voltage

I = electric current

R = resistance

Now put all the given values in this formula, we get the value of applied voltage.

[tex]V=(9A)\times (43\Omega)=387V[/tex]

Therefore, the applied voltage in the circuit will be, 387 V

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