lyn0wasMereF
lyn0wasMereF
18-08-2016
Mathematics
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inverse of y=x^2 -10x 27
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nobillionaireNobley
nobillionaireNobley
24-08-2016
[tex]y= x^{2} -10x+27 \\ y-2= x^{2} -10x+27-2 \\ y-2= x^{2} -10x+25 \\ y-2= (x-5)^{2} \\ x-5= \sqrt{y-2} \\ x=5+ \sqrt{y-2} [/tex]
Therefore, the inverse 0f y = x^2 - 10x + 27 is [tex]y = 5+ \sqrt{y-2} [/tex]
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