Respuesta :

caylus
Hello,

9m+n is divisible by 11 (remainder =0)

Since
[tex]5m+3n=11*k\\ m= \dfrac{11*k-3n}{5}\\ 9m=9*\dfrac{11*k-3n}{5}\\ 9m+n=9*\dfrac{11*k-3n}{5}+ \dfrac{5n}{5} \\ 9m+n= \dfrac{99k-27n+5n}{5}\\ 9m+n=11* \dfrac{9k-2n}{5}\\ [/tex]


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