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21-04-2020
Mathematics

contestada

What is the solution (q, r) to this system of linear equations?
12q + 3r= 15
-4q - 4r= -44
a.(-18,29)
b.(-2,13)
c.(8,-1)
d.(15,-44)

Respuesta :

Anisatunizzati Anisatunizzati

21-04-2020

Answer

r = 13

q = -2

step by step

12q + 3r = 15 | ×1 |

-4q - 4r = -44 | ×3 |

12q + 3r = 15

-12q - 12r = -132

____________+

-9r = -117

r = -117/-9

r = 13

12q + 3r = 15

12q + 3(13) = 15

12q + 39 = 15

12q = 15 - 39

12q = -24

q = -24/12

q = -2

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