leoaramos03 leoaramos03
  • 20-04-2020
  • Mathematics
contestada

What are the solutions to log6(x squared + 8) = 1 + log6(x)
x = -2 and x = --4
x =-1 and x = 8
x = 1 and x =-8
x = 2 and x = 4

Respuesta :

amna04352
amna04352 amna04352
  • 20-04-2020

Answer:

x = 2 and x = 4

Step-by-step explanation:

log6(x squared + 8) = 1 + log6(x)

log6(x squared + 8) = log6(6) + log6(x)

log6(x² + 8) = log6(6x)

x² + 8 = 6x

x² - 6x + 8 = 0

x² - 4x - 2x + 8 = 0

x(x - 4) - 2(x - 4) = 0

(x - 4)(x - 2) = 0

x = 2, 4

Answer Link
itzmegiannac itzmegiannac
  • 08-05-2021

Answer:

d

Step-by-step explanation:

i got it right on the review

Answer Link

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